Re: [ e^(-1i*a*x) ]^(1i / a*x) - e = 0 , substitute,a=2, solve,x . How many solutions ?

The answer should be:infinite

(e^B)^C=e^(B*C)

in your case B=-iax and C=i/(ax), so B*C=1

That simplifies your equation to e-e=0

any value of x will do, as long as it's unqual to 0.

Success!

Luc